3.2935 \(\int \frac {(2+3 x)^{11/2}}{(1-2 x)^{3/2} (3+5 x)^{5/2}} \, dx\)

Optimal. Leaf size=218 \[ \frac {18177329 \operatorname {EllipticF}\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )}{3781250 \sqrt {33}}+\frac {7 (3 x+2)^{9/2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}-\frac {107 \sqrt {1-2 x} (3 x+2)^{7/2}}{1815 (5 x+3)^{3/2}}-\frac {4553 \sqrt {1-2 x} (3 x+2)^{5/2}}{99825 \sqrt {5 x+3}}+\frac {380188 \sqrt {1-2 x} \sqrt {5 x+3} (3 x+2)^{3/2}}{831875}+\frac {17427983 \sqrt {1-2 x} \sqrt {5 x+3} \sqrt {3 x+2}}{8318750}+\frac {604915631 E\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{3781250 \sqrt {33}} \]

[Out]

604915631/124781250*EllipticE(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)[phone]/124781250*Elliptic
F(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)+7/11*(2+3*x)^(9/2)/(3+5*x)^(3/2)/(1-2*x)^(1/2)-107/1815
*(2+3*x)^(7/2)*(1-2*x)^(1/2)/(3+5*x)^(3/2)-4553/99825*(2+3*x)^(5/2)*(1-2*x)^(1/2)/(3+5*x)^(1/2)+380188/831875*
(2+3*x)^(3/2)*(1-2*x)^(1/2)*(3+5*x)^(1/2)[phone]/8318750*(1-2*x)^(1/2)*(2+3*x)^(1/2)*(3+5*x)^(1/2)

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Rubi [A]  time = 0.08, antiderivative size = 218, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {98, 150, 154, 158, 113, 119} \[ \frac {7 (3 x+2)^{9/2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}-\frac {107 \sqrt {1-2 x} (3 x+2)^{7/2}}{1815 (5 x+3)^{3/2}}-\frac {4553 \sqrt {1-2 x} (3 x+2)^{5/2}}{99825 \sqrt {5 x+3}}+\frac {380188 \sqrt {1-2 x} \sqrt {5 x+3} (3 x+2)^{3/2}}{831875}+\frac {17427983 \sqrt {1-2 x} \sqrt {5 x+3} \sqrt {3 x+2}}{8318750}+\frac {18177329 F\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{3781250 \sqrt {33}}+\frac {604915631 E\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{3781250 \sqrt {33}} \]

Antiderivative was successfully verified.

[In]

Int[(2 + 3*x)^(11/2)/((1 - 2*x)^(3/2)*(3 + 5*x)^(5/2)),x]

[Out]

(-107*Sqrt[1 - 2*x]*(2 + 3*x)^(7/2))/(1815*(3 + 5*x)^(3/2)) + (7*(2 + 3*x)^(9/2))/(11*Sqrt[1 - 2*x]*(3 + 5*x)^
(3/2)) - (4553*Sqrt[1 - 2*x]*(2 + 3*x)^(5/2))/(99825*Sqrt[3 + 5*x]) + (17427983*Sqrt[1 - 2*x]*Sqrt[2 + 3*x]*Sq
rt[3 + 5*x])/8318750 + (380188*Sqrt[1 - 2*x]*(2 + 3*x)^(3/2)*Sqrt[3 + 5*x])/831875 + (604915631*EllipticE[ArcS
in[Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33])/(3781250*Sqrt[33]) + (18177329*EllipticF[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]],
35/33])/(3781250*Sqrt[33])

Rule 98

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c -
a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] + Dist[1/(b*(b*e - a*
f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d
*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /;
FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 113

Int[Sqrt[(e_.) + (f_.)*(x_)]/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Simp[(2*Rt[-((b*e
- a*f)/d), 2]*EllipticE[ArcSin[Sqrt[a + b*x]/Rt[-((b*c - a*d)/d), 2]], (f*(b*c - a*d))/(d*(b*e - a*f))])/b, x
] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[b/(b*c - a*d), 0] && GtQ[b/(b*e - a*f), 0] &&  !LtQ[-((b*c - a*d)/d),
0] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[-(d/(b*c - a*d)), 0] && GtQ[d/(d*e - c*f), 0] &&  !LtQ[(b*c - a*d)
/b, 0])

Rule 119

Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol] :> Simp[(2*Rt[-(b/d
), 2]*EllipticF[ArcSin[Sqrt[a + b*x]/(Rt[-(b/d), 2]*Sqrt[(b*c - a*d)/b])], (f*(b*c - a*d))/(d*(b*e - a*f))])/(
b*Sqrt[(b*e - a*f)/b]), x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[(b*c - a*d)/b, 0] && GtQ[(b*e - a*f)/b, 0] &
& PosQ[-(b/d)] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[(d*e - c*f)/d, 0] && GtQ[-(d/b), 0]) &&  !(SimplerQ[c +
d*x, a + b*x] && GtQ[(-(b*e) + a*f)/f, 0] && GtQ[-(f/b), 0]) &&  !(SimplerQ[e + f*x, a + b*x] && GtQ[(-(d*e)
+ c*f)/f, 0] && GtQ[(-(b*e) + a*f)/f, 0] && (PosQ[-(f/d)] || PosQ[-(f/b)]))

Rule 150

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && LtQ[m, -1] && GtQ[n, 0] && IntegersQ[2*m, 2*n, 2*p]

Rule 154

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(h*(a + b*x)^m*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(m + n + p + 2)), x] + Dist[1/(d*f*(m + n
+ p + 2)), Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2) - h*(b*c*e*m + a*(d*e*(
n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x]
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegersQ[2*m, 2
*n, 2*p]

Rule 158

Int[((g_.) + (h_.)*(x_))/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol]
:> Dist[h/f, Int[Sqrt[e + f*x]/(Sqrt[a + b*x]*Sqrt[c + d*x]), x], x] + Dist[(f*g - e*h)/f, Int[1/(Sqrt[a + b*
x]*Sqrt[c + d*x]*Sqrt[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && SimplerQ[a + b*x, e + f*x] &&
SimplerQ[c + d*x, e + f*x]

Rubi steps

\begin {align*} \int \frac {(2+3 x)^{11/2}}{(1-2 x)^{3/2} (3+5 x)^{5/2}} \, dx &=\frac {7 (2+3 x)^{9/2}}{11 \sqrt {1-2 x} (3+5 x)^{3/2}}-\frac {1}{11} \int \frac {(2+3 x)^{7/2} \left (\frac {353}{2}+312 x\right )}{\sqrt {1-2 x} (3+5 x)^{5/2}} \, dx\\ &=-\frac {107 \sqrt {1-2 x} (2+3 x)^{7/2}}{1815 (3+5 x)^{3/2}}+\frac {7 (2+3 x)^{9/2}}{11 \sqrt {1-2 x} (3+5 x)^{3/2}}-\frac {2 \int \frac {(2+3 x)^{5/2} \left (\frac {38081}{4}+\frac {32493 x}{2}\right )}{\sqrt {1-2 x} (3+5 x)^{3/2}} \, dx}{1815}\\ &=-\frac {107 \sqrt {1-2 x} (2+3 x)^{7/2}}{1815 (3+5 x)^{3/2}}+\frac {7 (2+3 x)^{9/2}}{11 \sqrt {1-2 x} (3+5 x)^{3/2}}-\frac {4553 \sqrt {1-2 x} (2+3 x)^{5/2}}{99825 \sqrt {3+5 x}}-\frac {4 \int \frac {(2+3 x)^{3/2} \left (\frac {1361397}{8}+285141 x\right )}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{99825}\\ &=-\frac {107 \sqrt {1-2 x} (2+3 x)^{7/2}}{1815 (3+5 x)^{3/2}}+\frac {7 (2+3 x)^{9/2}}{11 \sqrt {1-2 x} (3+5 x)^{3/2}}-\frac {4553 \sqrt {1-2 x} (2+3 x)^{5/2}}{99825 \sqrt {3+5 x}}+\frac {380188 \sqrt {1-2 x} (2+3 x)^{3/2} \sqrt {3+5 x}}{831875}+\frac {4 \int \frac {\left (-\frac {48291975}{4}-\frac {156851847 x}{8}\right ) \sqrt {2+3 x}}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{2495625}\\ &=-\frac {107 \sqrt {1-2 x} (2+3 x)^{7/2}}{1815 (3+5 x)^{3/2}}+\frac {7 (2+3 x)^{9/2}}{11 \sqrt {1-2 x} (3+5 x)^{3/2}}-\frac {4553 \sqrt {1-2 x} (2+3 x)^{5/2}}{99825 \sqrt {3+5 x}}+\frac {17427983 \sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}}{8318750}+\frac {380188 \sqrt {1-2 x} (2+3 x)^{3/2} \sqrt {3+5 x}}{831875}-\frac {4 \int \frac {\frac {6892999929}{16}+\frac {5444240679 x}{8}}{\sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}} \, dx}{37434375}\\ &=-\frac {107 \sqrt {1-2 x} (2+3 x)^{7/2}}{1815 (3+5 x)^{3/2}}+\frac {7 (2+3 x)^{9/2}}{11 \sqrt {1-2 x} (3+5 x)^{3/2}}-\frac {4553 \sqrt {1-2 x} (2+3 x)^{5/2}}{99825 \sqrt {3+5 x}}+\frac {17427983 \sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}}{8318750}+\frac {380188 \sqrt {1-2 x} (2+3 x)^{3/2} \sqrt {3+5 x}}{831875}-\frac {18177329 \int \frac {1}{\sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}} \, dx}{7562500}-\frac {604915631 \int \frac {\sqrt {3+5 x}}{\sqrt {1-2 x} \sqrt {2+3 x}} \, dx}{41593750}\\ &=-\frac {107 \sqrt {1-2 x} (2+3 x)^{7/2}}{1815 (3+5 x)^{3/2}}+\frac {7 (2+3 x)^{9/2}}{11 \sqrt {1-2 x} (3+5 x)^{3/2}}-\frac {4553 \sqrt {1-2 x} (2+3 x)^{5/2}}{99825 \sqrt {3+5 x}}+\frac {17427983 \sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}}{8318750}+\frac {380188 \sqrt {1-2 x} (2+3 x)^{3/2} \sqrt {3+5 x}}{831875}+\frac {604915631 E\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{3781250 \sqrt {33}}+\frac {18177329 F\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{3781250 \sqrt {33}}\\ \end {align*}

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Mathematica [A]  time = 0.32, size = 141, normalized size = 0.65 \[ \frac {609979405 \sqrt {2-4 x} (5 x+3)^2 \operatorname {EllipticF}\left (\sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right ),-\frac {33}{2}\right )+10 \sqrt {3 x+2} \left (-242574750 x^4-1255998150 x^3+1267558775 x^2+2667846028 x+904528061\right ) \sqrt {5 x+3}-1209831262 \sqrt {2-4 x} (5 x+3)^2 E\left (\sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )|-\frac {33}{2}\right )}{249562500 \sqrt {1-2 x} (5 x+3)^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(2 + 3*x)^(11/2)/((1 - 2*x)^(3/2)*(3 + 5*x)^(5/2)),x]

[Out]

(10*Sqrt[2 + 3*x]*Sqrt[3 + 5*x]*(904528061 + 2667846028*x + 1267558775*x^2 - 1255998150*x^3 - 242574750*x^4) -
1209831262*Sqrt[2 - 4*x]*(3 + 5*x)^2*EllipticE[ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]], -33/2] + 609979405*Sqrt[2 -
4*x]*(3 + 5*x)^2*EllipticF[ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]], -33/2])/(249562500*Sqrt[1 - 2*x]*(3 + 5*x)^2)

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fricas [F]  time = 0.80, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (243 \, x^{5} + 810 \, x^{4} + 1080 \, x^{3} + 720 \, x^{2} + 240 \, x + 32\right )} \sqrt {5 \, x + 3} \sqrt {3 \, x + 2} \sqrt {-2 \, x + 1}}{500 \, x^{5} + 400 \, x^{4} - 235 \, x^{3} - 207 \, x^{2} + 27 \, x + 27}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(11/2)/(1-2*x)^(3/2)/(3+5*x)^(5/2),x, algorithm="fricas")

[Out]

integral((243*x^5 + 810*x^4 + 1080*x^3 + 720*x^2 + 240*x + 32)*sqrt(5*x + 3)*sqrt(3*x + 2)*sqrt(-2*x + 1)/(500
*x^5 + 400*x^4 - 235*x^3 - 207*x^2 + 27*x + 27), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (3 \, x + 2\right )}^{\frac {11}{2}}}{{\left (5 \, x + 3\right )}^{\frac {5}{2}} {\left (-2 \, x + 1\right )}^{\frac {3}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(11/2)/(1-2*x)^(3/2)/(3+5*x)^(5/2),x, algorithm="giac")

[Out]

integrate((3*x + 2)^(11/2)/((5*x + 3)^(5/2)*(-2*x + 1)^(3/2)), x)

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maple [C]  time = 0.03, size = 229, normalized size = 1.05 \[ -\frac {\sqrt {3 x +2}\, \sqrt {-2 x +1}\, \left (-7277242500 x^{5}-42531439500 x^{4}[phone] x^{3}[phone] x^{2}-6049156310 \sqrt {2}\, \sqrt {5 x +3}\, \sqrt {3 x +2}\, \sqrt {-2 x +1}\, x \EllipticE \left (\frac {\sqrt {110 x +66}}{11}, \frac {i \sqrt {66}}{2}\right )[phone] \sqrt {2}\, \sqrt {5 x +3}\, \sqrt {3 x +2}\, \sqrt {-2 x +1}\, x \EllipticF \left (\frac {\sqrt {110 x +66}}{11}, \frac {i \sqrt {66}}{2}\right )[phone] x -3629493786 \sqrt {2}\, \sqrt {5 x +3}\, \sqrt {3 x +2}\, \sqrt {-2 x +1}\, \EllipticE \left (\frac {\sqrt {110 x +66}}{11}, \frac {i \sqrt {66}}{2}\right )[phone] \sqrt {2}\, \sqrt {5 x +3}\, \sqrt {3 x +2}\, \sqrt {-2 x +1}\, \EllipticF \left (\frac {\sqrt {110 x +66}}{11}, \frac {i \sqrt {66}}{2}\right )[phone]\right )}{249562500 \left (5 x +3\right )^{\frac {3}{2}} \left (6 x^{2}+x -2\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*x+2)^(11/2)/(-2*x+1)^(3/2)/(5*x+3)^(5/2),x)

[Out]

-1/249562500*(3*x+2)^(1/2)*(-2*x+1)^(1/2)*(3049897025*2^(1/2)*EllipticF(1/11*(110*x+66)^(1/2),1/2*I*66^(1/2))*
x*(5*x+3)^(1/2)*(3*x+2)^(1/2)*(-2*x+1)^(1/2)-6049156310*2^(1/2)*EllipticE(1/11*(110*x+66)^(1/2),1/2*I*66^(1/2)
)*x*(5*x+3)^(1/2)*(3*x+2)^(1/2)*(-2*x+1)^(1/2)[phone]*2^(1/2)*(5*x+3)^(1/2)*(3*x+2)^(1/2)*(-2*x+1)^(1/2)*E
llipticF(1/11*(110*x+66)^(1/2),1/2*I*66^(1/2))-3629493786*2^(1/2)*(5*x+3)^(1/2)*(3*x+2)^(1/2)*(-2*x+1)^(1/2)*E
llipticE(1/11*(110*x+66)^(1/2),1/2*I*66^(1/2))-7277242500*x^5-42531439500*x^4+12906800250*x^3+105386556340*x^2
[phone]*x+18090561220)/(5*x+3)^(3/2)/(6*x^2+x-2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (3 \, x + 2\right )}^{\frac {11}{2}}}{{\left (5 \, x + 3\right )}^{\frac {5}{2}} {\left (-2 \, x + 1\right )}^{\frac {3}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(11/2)/(1-2*x)^(3/2)/(3+5*x)^(5/2),x, algorithm="maxima")

[Out]

integrate((3*x + 2)^(11/2)/((5*x + 3)^(5/2)*(-2*x + 1)^(3/2)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (3\,x+2\right )}^{11/2}}{{\left (1-2\,x\right )}^{3/2}\,{\left (5\,x+3\right )}^{5/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*x + 2)^(11/2)/((1 - 2*x)^(3/2)*(5*x + 3)^(5/2)),x)

[Out]

int((3*x + 2)^(11/2)/((1 - 2*x)^(3/2)*(5*x + 3)^(5/2)), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)**(11/2)/(1-2*x)**(3/2)/(3+5*x)**(5/2),x)

[Out]

Timed out

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